Article:<\/p>\n\n\n\n
I\u2019ve planned 300 hours for the details of Wiles\u2019 Proof of Fermat\u2019s Last Theorem.<\/p>\n\n\n\n
Update:<\/p>\n\n\n\n
from<\/p>\n\n\n\n
(a^d + b^d)^(1\/d) = (z^d)^(1\/d) is a norm to a side of projection to the isometric space.
The cases are (the right side : the left side), to consider
(1) rational number : rational number
(2) irrational number : rational number
(3) rational number : irrational number
(4) irrational number : irrational number
E.g. x = y = 2,
(x^d + y^d)^(1\/d) = (2x^d)^(1\/d) = (z^d)^(1\/d),
(x^(d+1))^(1\/d) = (z^d)^(1\/d),
x^2 = z in the inverse square space, (1) or (4) of T.
E.g. x = y \u2260 2,
(x^d + y^d)^(1\/d) = (2x^d)^(1\/d) = (z^d)^(1\/d),
2^(1\/d) \u00d7 x = 2^(1\/d) \u00d7 y = z in an isometric space, {2^(1\/d) \u2192 \u03b2 | \u03b2 \u2208 \u03b1}, (4) of T.<\/p>\n\n\n\n
to<\/p>\n\n\n\n
If (a^d + b^d)^(1\/d) = (z^d)^(1\/d) is a norm to a side of projection to the isometric space.
The cases are (the right side : the left side), to consider
(1) rational number : rational number
(2) irrational number : rational number
(3) rational number : irrational number
(4) irrational number : irrational number
E.g. x = y = 2,
if (x^d + y^d)^(1\/d) = (2x^d)^(1\/d) = (z^d)^(1\/d), (x^(d+1))^(1\/d) = (z^d)^(1\/d),
x^((d+1)\/d) \u2260 z^1, d=1 \u2192 x^2 is in the inverse square space, but (2) or (4) of F.
E.g. x = y \u2260 2,
if (x^d + y^d)^(1\/d) = (2x^d)^(1\/d) = (z^d)^(1\/d),
2^(1\/d) \u00d7 x^1 = 2^(1\/d) \u00d7 y^1 \u2260 z^1 in an isometric space, {2^(1\/d) \u2192 \u03b2 | \u03b2 \u2208 \u03b1}, (2) or (4) of F.<\/p>\n\n\n\n
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